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In physics, the center-of-momentum frame (COM frame), also known as zero-momentum frame, is the inertial frame in which the total momentum of the system vanishes. It is unique up to velocity, but not origin. The center of momentum of a system is not a location, but a collection of relative momenta/velocities: a reference frame. Thus "center of momentum" is a short for "center-of-momentum frame".
A special case of the center-of-momentum frame is the center-of-mass frame: an inertial frame in which the center of mass (which is a single point) remains at the origin. In all center-of-momentum frames, the center of mass is at rest, but it is not necessarily at the origin of the coordinate system. In special relativity, the COM frame is necessarily unique only when the system is isolated.
Properties
General
The center of momentum frame is defined as the inertial frame in which the sum of the linear momenta of all particles is equal to 0. Let S denote the laboratory reference system and S′ denote the center-of-momentum reference frame. Using a Galilean transformation, the particle velocity in S′ is
where
is the velocity of the mass center. The total momentum in the center-of-momentum system then vanishes:
Also, the total energy of the system is the minimal energy as seen from all inertial reference frames.
Special relativity
In relativity, the COM frame exists for an isolated massive system. This is a consequence of Noether's theorem. In the COM frame the total energy of the system is the rest energy, and this quantity (when divided by the factor c2, where c is the speed of light) gives the invariant mass (rest mass) of the system:
The invariant mass of the system is given in any inertial frame by the relativistic invariant relation
but for zero momentum the momentum term (p/c)2 vanishes and thus the total energy coincides with the rest energy.
Systems that have nonzero energy but zero rest mass (such as photons moving in a single direction, or, equivalently, plane electromagnetic waves) do not have COM frames, because there is no frame in which they have zero net momentum. Due to the invariance of the speed of light, a massless system must travel at the speed of light in any frame, and always possesses a net momentum. Its energy is – for each reference frame – equal to the magnitude of momentum multiplied by the speed of light:
Two-body problem
An example of the usage of this frame is given below – in a two-body collision, not necessarily elastic (where kinetic energy is conserved). The COM frame can be used to find the momentum of the particles much easier than in a lab frame: the frame where the measurement or calculation is done. The situation is analyzed using Galilean transformations and conservation of momentum (for generality, rather than kinetic energies alone), for two particles of mass m1 and m2, moving at initial velocities (before collision) u1 and u2 respectively. The transformations are applied to take the velocity of the frame from the velocity of each particle from the lab frame (unprimed quantities) to the COM frame (primed quantities):
where V is the velocity of the COM frame. Since V is the velocity of the COM, i.e. the time derivative of the COM location R (position of the center of mass of the system):
so at the origin of the COM frame, R' = 0, this implies
The same results can be obtained by applying momentum conservation in the lab frame, where the momenta are p1 and p2:
and in the COM frame, where it is asserted definitively that the total momenta of the particles, p1' and p2', vanishes:
Using the COM frame equation to solve for V returns the lab frame equation above, demonstrating any frame (including the COM frame) may be used to calculate the momenta of the particles. It has been established that the velocity of the COM frame can be removed from the calculation using the above frame, so the momenta of the particles in the COM frame can be expressed in terms of the quantities in the lab frame (i.e. the given initial values):
Notice that the relative velocity in the lab frame of particle 1 to 2 is
and the 2-body reduced mass is
so the momenta of the particles compactly reduce to
This is a substantially simpler calculation of the momenta of both particles; the reduced mass and relative velocity can be calculated from the initial velocities in the lab frame and the masses, and the momentum of one particle is simply the negative of the other. The calculation can be repeated for final velocities v1 and v2 in place of the initial velocities u1 and u2, since after the collision the velocities still satisfy the above equations:
so at the origin of the COM frame, R = 0, this implies after the collision
In the lab frame, the conservation of momentum fully reads:
This equation does not imply that
instead, it simply indicates the total mass M multiplied by the velocity of the centre of mass V is the total momentum P of the system:
Similar analysis to the above obtains
where the final relative velocity in the lab frame of particle 1 to 2 is
See also
- Laboratory frame of reference
- Breit frame
References
This article needs additional citations for verification Please help improve this article by adding citations to reliable sources Unsourced material may be challenged and removed Find sources Center of momentum frame news newspapers books scholar JSTOR September 2024 Learn how and when to remove this message In physics the center of momentum frame COM frame also known as zero momentum frame is the inertial frame in which the total momentum of the system vanishes It is unique up to velocity but not origin The center of momentum of a system is not a location but a collection of relative momenta velocities a reference frame Thus center of momentum is a short for center of momentum frame A special case of the center of momentum frame is the center of mass frame an inertial frame in which the center of mass which is a single point remains at the origin In all center of momentum frames the center of mass is at rest but it is not necessarily at the origin of the coordinate system In special relativity the COM frame is necessarily unique only when the system is isolated PropertiesGeneral The center of momentum frame is defined as the inertial frame in which the sum of the linear momenta of all particles is equal to 0 Let S denote the laboratory reference system and S denote the center of momentum reference frame Using a Galilean transformation the particle velocity in S is v v Vc displaystyle v v V text c where Vc imivi imi displaystyle V text c frac sum i m i v i sum i m i is the velocity of the mass center The total momentum in the center of momentum system then vanishes ipi imivi imi vi Vc imivi imi jmjvj jmj imivi jmjvj 0 displaystyle sum i p i sum i m i v i sum i m i v i V text c sum i m i v i sum i m i frac sum j m j v j sum j m j sum i m i v i sum j m j v j 0 Also the total energy of the system is the minimal energy as seen from all inertial reference frames Special relativity In relativity the COM frame exists for an isolated massive system This is a consequence of Noether s theorem In the COM frame the total energy of the system is the rest energy and this quantity when divided by the factor c2 where c is the speed of light gives the invariant mass rest mass of the system m0 E0c2 displaystyle m 0 frac E 0 c 2 The invariant mass of the system is given in any inertial frame by the relativistic invariant relation m02 Ec2 2 pc 2 displaystyle m 0 2 left frac E c 2 right 2 left frac p c right 2 but for zero momentum the momentum term p c 2 vanishes and thus the total energy coincides with the rest energy Systems that have nonzero energy but zero rest mass such as photons moving in a single direction or equivalently plane electromagnetic waves do not have COM frames because there is no frame in which they have zero net momentum Due to the invariance of the speed of light a massless system must travel at the speed of light in any frame and always possesses a net momentum Its energy is for each reference frame equal to the magnitude of momentum multiplied by the speed of light E pc displaystyle E pc Two body problemAn example of the usage of this frame is given below in a two body collision not necessarily elastic where kinetic energy is conserved The COM frame can be used to find the momentum of the particles much easier than in a lab frame the frame where the measurement or calculation is done The situation is analyzed using Galilean transformations and conservation of momentum for generality rather than kinetic energies alone for two particles of mass m1 and m2 moving at initial velocities before collision u1 and u2 respectively The transformations are applied to take the velocity of the frame from the velocity of each particle from the lab frame unprimed quantities to the COM frame primed quantities u1 u1 V u2 u2 V displaystyle mathbf u 1 prime mathbf u 1 mathbf V quad mathbf u 2 prime mathbf u 2 mathbf V where V is the velocity of the COM frame Since V is the velocity of the COM i e the time derivative of the COM location R position of the center of mass of the system dRdt ddt m1r1 m2r2m1 m2 m1u1 m2u2m1 m2 V displaystyle begin aligned frac rm d mathbf R rm d t amp frac rm d rm d t left frac m 1 mathbf r 1 m 2 mathbf r 2 m 1 m 2 right amp frac m 1 mathbf u 1 m 2 mathbf u 2 m 1 m 2 amp mathbf V end aligned so at the origin of the COM frame R 0 this implies m1u1 m2u2 0 displaystyle m 1 mathbf u 1 prime m 2 mathbf u 2 prime boldsymbol 0 The same results can be obtained by applying momentum conservation in the lab frame where the momenta are p1 and p2 V p1 p2m1 m2 m1u1 m2u2m1 m2 displaystyle mathbf V frac mathbf p 1 mathbf p 2 m 1 m 2 frac m 1 mathbf u 1 m 2 mathbf u 2 m 1 m 2 and in the COM frame where it is asserted definitively that the total momenta of the particles p1 and p2 vanishes p1 p2 m1u1 m2u2 0 displaystyle mathbf p 1 prime mathbf p 2 prime m 1 mathbf u 1 prime m 2 mathbf u 2 prime boldsymbol 0 Using the COM frame equation to solve for V returns the lab frame equation above demonstrating any frame including the COM frame may be used to calculate the momenta of the particles It has been established that the velocity of the COM frame can be removed from the calculation using the above frame so the momenta of the particles in the COM frame can be expressed in terms of the quantities in the lab frame i e the given initial values p1 m1u1 m1 u1 V m1m2m1 m2 u1 u2 m2u2 p2 displaystyle begin aligned mathbf p 1 prime amp m 1 mathbf u 1 prime amp m 1 left mathbf u 1 mathbf V right frac m 1 m 2 m 1 m 2 left mathbf u 1 mathbf u 2 right amp m 2 mathbf u 2 prime mathbf p 2 prime end aligned Notice that the relative velocity in the lab frame of particle 1 to 2 is Du u1 u2 displaystyle Delta mathbf u mathbf u 1 mathbf u 2 and the 2 body reduced mass is m m1m2m1 m2 displaystyle mu frac m 1 m 2 m 1 m 2 so the momenta of the particles compactly reduce to p1 p2 mDu displaystyle mathbf p 1 prime mathbf p 2 prime mu Delta mathbf u This is a substantially simpler calculation of the momenta of both particles the reduced mass and relative velocity can be calculated from the initial velocities in the lab frame and the masses and the momentum of one particle is simply the negative of the other The calculation can be repeated for final velocities v1 and v2 in place of the initial velocities u1 and u2 since after the collision the velocities still satisfy the above equations dRdt ddt m1r1 m2r2m1 m2 m1v1 m2v2m1 m2 V displaystyle begin aligned frac rm d mathbf R rm d t amp frac rm d rm d t left frac m 1 mathbf r 1 m 2 mathbf r 2 m 1 m 2 right amp frac m 1 mathbf v 1 m 2 mathbf v 2 m 1 m 2 amp mathbf V end aligned so at the origin of the COM frame R 0 this implies after the collision m1v1 m2v2 0 displaystyle m 1 mathbf v 1 prime m 2 mathbf v 2 prime boldsymbol 0 In the lab frame the conservation of momentum fully reads m1u1 m2u2 m1v1 m2v2 m1 m2 V displaystyle m 1 mathbf u 1 m 2 mathbf u 2 m 1 mathbf v 1 m 2 mathbf v 2 m 1 m 2 mathbf V This equation does not imply that m1u1 m1v1 m1V m2u2 m2v2 m2V displaystyle m 1 mathbf u 1 m 1 mathbf v 1 m 1 mathbf V quad m 2 mathbf u 2 m 2 mathbf v 2 m 2 mathbf V instead it simply indicates the total mass M multiplied by the velocity of the centre of mass V is the total momentum P of the system P p1 p2 m1 m2 V MV displaystyle begin aligned mathbf P amp mathbf p 1 mathbf p 2 amp m 1 m 2 mathbf V amp M mathbf V end aligned Similar analysis to the above obtains p1 p2 mDv mDu displaystyle mathbf p 1 prime mathbf p 2 prime mu Delta mathbf v mu Delta mathbf u where the final relative velocity in the lab frame of particle 1 to 2 is Dv v1 v2 Du displaystyle Delta mathbf v mathbf v 1 mathbf v 2 Delta mathbf u See alsoLaboratory frame of reference Breit frameReferencesDynamics and Relativity J R Forshaw A G Smith Wiley 2009 ISBN 978 0 470 01460 8 Classical Mechanics T W B Kibble European Physics Series 1973 ISBN 0 07 084018 0 An Introduction to Mechanics D Kleppner R J Kolenkow Cambridge University Press 2010 ISBN 978 0 521 19821 9